hdu 2070 Fibbonacci Number(斐波那契数)

共 1080字,需浏览 3分钟

 ·

2021-07-30 19:42

Fibbonacci Number

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 44158    Accepted Submission(s): 19610


Problem Description

Your objective for this question is to develop a program which will generate a fibbonacci number. The fibbonacci function is defined as such:

f(0) = 0
f(1) = 1
f(n) = f(n-1) + f(n-2)

Your program should be able to handle values of n in the range 0 to 50.

 


Input

Each test case consists of one integer n in a single line where 0≤n≤50. The input is terminated by -1.

 


Output

Print out the answer in a single line for each test case.

 


Sample Input

3
4
5
-1

 


Sample Output

2
3
5

Hint

Note:


you can use 64bit integer: __int64



代码:

#include<stdio.h>
int main()
{
long long a[55];
int i,n;
a[0] = 0;
a[1] = 1;
for(i=2;i<=50;i++)
a[i] = a[i-1]+a[i-2];
while(scanf("%d",&n)!=EOF)
{
if(n==-1)
break;
printf("%lld\n",a[n]);
}
return 0;
}


浏览 33
点赞
评论
收藏
分享

手机扫一扫分享

分享
举报
评论
图片
表情
推荐
点赞
评论
收藏
分享

手机扫一扫分享

分享
举报