30个极简Python代码,拿走就能用!
杰哥的IT之旅
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2021-02-28 19:04
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作者丨Fatos Morina
来源丨Python 技术
编辑丨极市平台
1 重复元素判定
def all_unique(lst):
return len(lst)== len(set(lst))
x = [1,1,2,2,3,2,3,4,5,6]
y = [1,2,3,4,5]
all_unique(x) # False
all_unique(y) # True
2 字符元素组成判定
from collections import Counter
def anagram(first, second):
return Counter(first) == Counter(second)
anagram("abcd3", "3acdb") # True
3 内存占用
import sys
variable = 30
print(sys.getsizeof(variable)) # 24
4 字节占用
def byte_size(string):
return(len(string.encode('utf-8')))
byte_size('') # 4
byte_size('Hello World') # 11
5 打印 N 次字符串
n = 2
s ="Programming"
print(s * n)
# ProgrammingProgramming
6 大写第一个字母
s = "programming is awesome"
print(s.title())
# Programming Is Awesome
7 分块
from math import ceil
def chunk(lst, size):
return list(
map(lambda x: lst[x * size:x * size + size],
list(range(0, ceil(len(lst) / size)))))
chunk([1,2,3,4,5],2)
# [[1,2],[3,4],5]
8 压缩
def compact(lst):
return list(filter(bool, lst))
compact([0, 1, False, 2, '', 3, 'a', 's', 34])
# [ 1, 2, 3, 'a', 's', 34 ]
9 解包
array = [['a', 'b'], ['c', 'd'], ['e', 'f']]
transposed = zip(*array)
print(transposed)
# [('a', 'c', 'e'), ('b', 'd', 'f')]
10 链式对比
a = 3
print( 2 < a < 8) # True
print(1 == a < 2) # False
11 逗号连接
hobbies = ["basketball", "football", "swimming"]
print("My hobbies are: " + ", ".join(hobbies))
# My hobbies are: basketball, football, swimming
12 元音统计
import re
def count_vowels(str):
return len(len(re.findall(r'[aeiou]', str, re.IGNORECASE)))
count_vowels('foobar') # 3
count_vowels('gym') # 0
13 首字母小写
def decapitalize(string):
return str[:1].lower() + str[1:]
decapitalize('FooBar') # 'fooBar'
decapitalize('FooBar') # 'fooBar'
14 展开列表
def spread(arg):
ret = []
for i in arg:
if isinstance(i, list):
ret.extend(i)
else:
ret.append(i)
return ret
def deep_flatten(lst):
result = []
result.extend(
spread(list(map(lambda x: deep_flatten(x) if type(x) == list else x, lst))))
return result
deep_flatten([1, [2], [[3], 4], 5]) # [1,2,3,4,5]
15 列表的差
def difference(a, b):
set_a = set(a)
set_b = set(b)
comparison = set_a.difference(set_b)
return list(comparison)
difference([1,2,3], [1,2,4]) # [3]
16 通过函数取差
def difference_by(a, b, fn):
b = set(map(fn, b))
return [item for item in a if fn(item) not in b]
from math import floor
difference_by([2.1, 1.2], [2.3, 3.4],floor) # [1.2]
difference_by([{ 'x': 2 }, { 'x': 1 }], [{ 'x': 1 }], lambda v : v['x'])
# [ { x: 2 } ]
17 链式函数调用
def add(a, b):
return a + b
def subtract(a, b):
return a - b
a, b = 4, 5
print((subtract if a > b else add)(a, b)) # 9
18 检查重复项
def has_duplicates(lst):
return len(lst) != len(set(lst))
x = [1,2,3,4,5,5]
y = [1,2,3,4,5]
has_duplicates(x) # True
has_duplicates(y) # False
19 合并两个字典
def merge_two_dicts(a, b):
c = a.copy() # make a copy of a
c.update(b) # modify keys and values of a with the once from b
return c
a={'x':1,'y':2}
b={'y':3,'z':4}
print(merge_two_dicts(a,b))
#{'y':3,'x':1,'z':4}
在 Python 3.5 或更高版本中,我们也可以用以下方式合并字典:
def merge_dictionaries(a, b)
return {**a, **b}
a = { 'x': 1, 'y': 2}
b = { 'y': 3, 'z': 4}
print(merge_dictionaries(a, b))
# {'y': 3, 'x': 1, 'z': 4}
20 将两个列表转化为字典
def to_dictionary(keys, values):
return dict(zip(keys, values))
keys = ["a", "b", "c"]
values = [2, 3, 4]
print(to_dictionary(keys, values))
#{'a': 2, 'c': 4, 'b': 3}
21 使用枚举
list = ["a", "b", "c", "d"]
for index, element in enumerate(list):
print("Value", element, "Index ", index, )
# ('Value', 'a', 'Index ', 0)
# ('Value', 'b', 'Index ', 1)
#('Value', 'c', 'Index ', 2)
# ('Value', 'd', 'Index ', 3)
22 执行时间
import time
start_time = time.time()
a = 1
b = 2
c = a + b
print(c) #3
end_time = time.time()
total_time = end_time - start_time
print("Time: ", total_time)
# ('Time: ', 1.1205673217773438e-05)
23 Try else
try:
2*3
except TypeError:
print("An exception was raised")
else:
print("Thank God, no exceptions were raised.")
#Thank God, no exceptions were raised.
24 元素频率
def most_frequent(list):
return max(set(list), key = list.count)
list = [1,2,1,2,3,2,1,4,2]
most_frequent(list)
25 回文序列
def palindrome(string):
from re import sub
s = sub('[\W_]', '', string.lower())
return s == s[::-1]
palindrome('taco cat') # True
26 不使用 if-else 的计算子
import operator
action = {
"+": operator.add,
"-": operator.sub,
"/": operator.truediv,
"*": operator.mul,
"**": pow
}
print(action['-'](50, 25))
27 Shuffle
from copy import deepcopy
from random import randint
def shuffle(lst):
temp_lst = deepcopy(lst)
m = len(temp_lst)
while (m):
m -= 1
i = randint(0, m)
temp_lst[i] = temp_lst[i], temp_lst[m]
return temp_lst
foo = [1,2,3]
# [2,3,1] , foo = [1,2,3]
28 展开列表
def spread(arg):
ret = []
for i in arg:if isinstance(i, list):
ret.extend(i)
else:
ret.append(i)
return ret
spread([1,2,3,[4,5,6],[7],8,9]) # [1,2,3,4,5,6,7,8,9]
29 交换值
def swap(a, b):
return b, a
a, b = -1, 14
swap(a, b) # (14, -1)
spread([1,2,3,[4,5,6],[7],8,9]) # [1,2,3,4,5,6,7,8,9
30 字典默认值
d = {'a': 1, 'b': 2}print(d.get('c', 3)) # 3
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