相见恨晚的 Python 内置库:itertools
>>> import itertools
>>> x = itertools.accumulate(range(10))
>>> print(list(x))
[0, 1, 3, 6, 10, 15, 21, 28, 36, 45]
>>> x = itertools.chain(range(3), range(4), [3,2,1])
>>> print(list(x))
[0, 1, 2, 0, 1, 2, 3, 3, 2, 1]
>>> x = itertools.combinations(range(4), 3)
>>> print(list(x))
[(0, 1, 2), (0, 1, 3), (0, 2, 3), (1, 2, 3)]
>>> x = itertools.combinations_with_replacement('ABC', 2)
>>> print(list(x))
[('A', 'A'), ('A', 'B'), ('A', 'C'), ('B', 'B'), ('B', 'C'), ('C', 'C')]
>>> x = itertools.compress(range(5), (True, False, True, True, False))
>>> print(list(x))
[0, 2, 3]
>>> x = itertools.count(start=20, step=-1)
>>> print(list(itertools.islice(x, 0, 10, 1)))
[20, 19, 18, 17, 16, 15, 14, 13, 12, 11]
>>> x = itertools.cycle('ABC')
>>> print(list(itertools.islice(x, 0, 10, 1)))
['A', 'B', 'C', 'A', 'B', 'C', 'A', 'B', 'C', 'A']
>>> x = itertools.dropwhile(lambda e: e < 5, range(10))
>>> print(list(x))
[5, 6, 7, 8, 9]
>>> x = itertools.filterfalse(lambda e: e < 5, (1, 5, 3, 6, 9, 4))
>>> print(list(x))
[5, 6, 9]
>>> x = itertools.groupby(range(10), lambda x: x < 5 or x > 8)
>>> for condition, numbers in x:
... print(condition, list(numbers))
True [0, 1, 2, 3, 4]
False [5, 6, 7, 8]
True [9]
>>> x = itertools.islice(range(10), 0, 9, 2)
>>> print(list(x))
[0, 2, 4, 6, 8]
>>> x = itertools.permutations(range(4), 3)
>>> print(list(x))
[(0, 1, 2), (0, 1, 3), (0, 2, 1), (0, 2, 3), (0, 3, 1), (0, 3, 2), (1, 0, 2), (1, 0, 3), (1, 2, 0), (1, 2, 3), (1, 3, 0), (1, 3, 2), (2, 0, 1), (2, 0,3), (2, 1, 0), (2, 1, 3), (2, 3, 0), (2, 3, 1), (3, 0, 1), (3, 0, 2), (3, 1, 0), (3, 1, 2), (3, 2, 0), (3, 2, 1)]
>>> x = itertools.product('ABC', range(3))
>>>
>>> print(list(x))
[('A', 0), ('A', 1), ('A', 2), ('B', 0), ('B', 1), ('B', 2), ('C', 0), ('C', 1), ('C', 2)]
>>> x = itertools.repeat(0, 5)
>>> print(list(x))
[0, 0, 0, 0, 0]
>>> x = itertools.starmap(str.islower, 'aBCDefGhI')
>>> print(list(x))
[True, False, False, False, True, True, False, True, False]
>>> x = itertools.takewhile(lambda e: e < 5, range(10))
>>> print(list(x))
[0, 1, 2, 3, 4]
>>> x = itertools.tee(range(10), 2)
>>> for letters in x:
... print(list(letters))
...
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> x = itertools.zip_longest(range(3), range(5))
>>> y = zip(range(3), range(5))
>>> print(list(x))
[(0, 0), (1, 1), (2, 2), (None, 3), (None, 4)]
>>> print(list(y))
[(0, 0), (1, 1), (2, 2)]
来源:忆先
链接:segmentfault.com/a/1190000008590958
福利
入门Python的最强三件套《ThinkPython》、《简明Python教程》、《Python进阶》的PDF电子版已打包提供给大家,关注下方公众号,在后台回复关键字「P3」即可获取。
推荐阅读:
入门: 最全的零基础学Python的问题 | 零基础学了8个月的Python | 实战项目 |学Python就是这条捷径
干货:爬取豆瓣短评,电影《后来的我们》 | 38年NBA最佳球员分析 | 从万众期待到口碑扑街!唐探3令人失望 | 笑看新倚天屠龙记 | 灯谜答题王 |用Python做个海量小姐姐素描图 |碟中谍这么火,我用机器学习做个迷你推荐系统电影
趣味:弹球游戏 | 九宫格 | 漂亮的花 | 两百行Python《天天酷跑》游戏!
AI: 会做诗的机器人 | 给图片上色 | 预测收入 | 碟中谍这么火,我用机器学习做个迷你推荐系统电影
小工具: Pdf转Word,轻松搞定表格和水印! | 一键把html网页保存为pdf!| 再见PDF提取收费! | 用90行代码打造最强PDF转换器,word、PPT、excel、markdown、html一键转换 | 制作一款钉钉低价机票提示器! |60行代码做了一个语音壁纸切换器天天看小姐姐!|
年度爆款文案
点阅读原文,领AI全套资料!
评论