LeetCode刷题实战35: 搜索插入位置
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今天和大家聊的问题叫做 搜索插入位置,我们先来看题面:
https://leetcode-cn.com/problems/search-insert-position/
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array.
题意
样例
示例 1:
输入: [1,3,5,6], 5
输出: 2
示例 2:
输入: [1,3,5,6], 2
输出: 1
示例 3:
输入: [1,3,5,6], 7
输出: 4
示例 4:
输入: [1,3,5,6], 0
输出: 0
题解
public int searchInsert(int[] nums, int target) {
if (nums.length == 0) {
return 0;
}
for (int i = 0; i < nums.length; i++) {
if (nums[i] >= target)
return i;
}
return nums.length;
}
class Solution {
public int searchInsert(int[] nums, int target) {
int n = nums.length;
int left = 0, right = n - 1, ans = n;
while (left <= right) {
int mid = ((right - left) >> 1) + left;
if (target <= nums[mid]) {
ans = mid;
right = mid - 1;
} else {
left = mid + 1;
}
}
return ans;
}
}
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