客户让我用Python帮他买彩票
恋习Python
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2021-05-15 05:21
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本文链接:https://blog.csdn.net/m0_54218263/article/details/116001249
一、需求介绍
然后,根据这个方案,有可能会买中,但是也有可能买不中,于是,客户希望我可以统计出来在100天中,按照这种方法,连续6次以及6次以上的购买彩票才能够命中一次奖的次数以及分别所对应的时间,对于这个案例,我们下面详细分析。
二、以极速飞艇为例进行数据分析
def reverse_list(lst):
"""
准换列表的先后顺序
:param lst: 原始列表
:return: 新的列表
"""
return [ele for ele in reversed(lst)]
low_list = ["01", "02", "03", "04", "05"]
# 设置比较小的数字的列表
high_list = ["06", "07", "08", "09", "10"]
# 设置比较大的数字的列表
N = 0
# 设置一个数字N来记录一共有多少期可以购买
n = 0
# 设置一个数字n来记录命中了多少期彩票
record_number = 1
# 设置记录数据的一个判断值
list_data_number = []
# 设置一个空的列表来存储一天之中的连续挂掉的期数
dict_time_record = {}
# 设置一个空的字典来存储连挂掉的期数满足所列条件的时间节点
for k in range(1152):
# 循环遍历所有的数据点
if k < 1150:
new_result1 = reverse_list(new_response["result"]["data"])[k]
# 第一期数据
new_result2 = reverse_list(new_response["result"]["data"])[k + 1]
# 第二期数据
new_result3 = reverse_list(new_response["result"]["data"])[k + 2]
# 第三期数据
data1 = new_result1['preDrawCode'].split(',')
# 第一期数据
data2 = new_result2['preDrawCode'].split(',')
# 第二期数据
data3 = new_result3['preDrawCode'].split(',')
# 第三期数据
for m in range(10):
# 通过循环来判断是否满足购买的条件,并且实现一定的功能
if m == 0:
if data2[0] == data1[1]:
# 如果相等就要结束循环
N += 1
# 可以购买的期数应该要自加一
if (data2[0] in low_list and data3[0] in low_list) or (data2[0] in high_list and data3[0] in high_list):
n += 1
# 命中的期数应该要自加一
# 如果命中了的话,本轮结束,开启下一轮
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
# 如果已经有了这个键,那么值添加时间点
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
# 如果没有这个键,那么添加一个键值对,值为一个列表,而且初始化为当前的时间
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
record_number = 1
# 初始化下一轮的开始
else:
record_number += 1
# 如果没有命中的话,次数就应该要自加一
break
# 如果满足相等的条件就要结束循环
elif m == 9:
# 与上面差不多的算法
if data2[9] == data1[8]:
# 如果相等
N += 1
if (data2[9] in low_list and data3[9] in low_list) or (data2[9] in high_list and data3[9] in high_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
record_number = 1
else:
record_number += 1
break
else:
# 与上面差不多的算法
if data2[m] == data1[m + 1] or data2[m] == data1[m - 1]:
# 如果相等
N += 1
if (data2[m] in low_list and data3[m] in low_list) or (data2[m] in high_list and data3[m] in high_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
record_number = 1
else:
record_number += 1
break
print(f"日期:{new_response['result']['data'][0]['preDrawTime'][:10]},总的梯子数为{N}个,一共有{n}次命中,一共有{N - n}次挂了")
# 打印时间,以及,可以购买的期数,命中的期数,没有命中的期数
list_data_number.sort()
# 按照大小顺序来进行排序
dict_record = {}
# 设置空字典进行记录
for i in list_data_number:
if f"{i}" in dict_record.keys(): # 判断是否已经有了这个数字?
dict_record[f"{i}"] += 1
# 如果有的话,那么就会自加一
else: # 如果没有的话,那么就会创建并且赋值等于 1
dict_record[f"{i}"] = 1
# 创建一个新的字典元素,然后进行赋值为 1
for j in dict_record.keys():
if (int(j) >= 6) and (int(j) < 15):
# 实际的结果表明,我们需要的是大于等于6期的数据,而没有出现大于15的数据,因此有这样的一个关系式
print(f"买{j}次才中奖的次数为{dict_record[j]}")
# 打印相关信息
print(dict_time_record[j])
str0 = ""
for letter in dict_time_record[j]:
str0 += letter
str0 += ", "
print(str0)
# 打印相关信息
data_list = []
for h in range(31):
data_list.append(f'1-{h + 1}')
for h in range(28):
data_list.append(f'2-{h + 1}')
for h in range(31):
data_list.append(f'3-{h + 1}')
for h in range(20):
data_list.append(f'4-{h + 1}')
通过上述的代码,我们即实现了时间列表的设置,然后我们循环遍历这个列表访问不同日期的彩票数据即就是得到了不同时间的数据,然后再利用上述的分析方法来进行数据分析,即就是可以得到了多天的彩票数据分析的结果了。
三、完整的代码展示
import requests
import chardet
import json
import xlwt # excel 表格数据处理的对应模块
def reverse_list(lst):
"""
准换列表的先后顺序
:param lst: 原始列表
:return: 新的列表
"""
return [ele for ele in reversed(lst)]
data_list = []
for h in range(31):
data_list.append(f'1-{h + 1}')
for h in range(28):
data_list.append(f'2-{h + 1}')
for h in range(31):
data_list.append(f'3-{h + 1}')
for h in range(20):
data_list.append(f'4-{h + 1}')
wb = xlwt.Workbook() # 创建 excel 表格
sh = wb.add_sheet('彩票分析数据处理') # 创建一个 表单
sh.write(0, 0, "日期")
sh.write(0, 1, "梯子数目")
sh.write(0, 2, "命中数目")
sh.write(0, 3, "挂的数目")
sh.write(0, 4, "6次中的数目")
sh.write(0, 5, "6次中的时间")
sh.write(0, 6, "7次中的数目")
sh.write(0, 7, "7次中的时间")
sh.write(0, 8, "8次中的数目")
sh.write(0, 9, "8次中的时间")
sh.write(0, 10, "9次中的数目")
sh.write(0, 11, "9次中的时间")
sh.write(0, 12, "10次中的数目")
sh.write(0, 13, "10次中的时间")
sh.write(0, 14, "11次中的数目")
sh.write(0, 15, "11次中的时间")
sh.write(0, 16, "12次中的数目")
sh.write(0, 17, "12次中的时间")
sh.write(0, 18, "13次中的数目")
sh.write(0, 19, "13次中的时间")
sh.write(0, 20, "14次中的数目")
sh.write(0, 21, "14次中的时间")
# wb.save('test4.xls')
sheet_seek_position = 1
# 设置表格的初始位置为 1
for data in data_list:
low_list = ["01", "02", "03", "04", "05"]
high_list = ["06", "07", "08", "09", "10"]
N = 0
n = 0
url = f'https://api.api68.com/pks/getPksHistoryList.do?date=2021-{data}&lotCode=10037'
headers = {
'User-Agent':
'Mozilla/5.0 (Windows NT 10.0; Win64; x64) '
'AppleWebKit/537.36 (KHTML, like Gecko) '
'Chrome/90.0.4430.72 Safari/537.36'
}
response = requests.get(url=url, headers=headers)
response.encoding = chardet.detect(response.content)['encoding']
new_response = json.loads(response.text)
sh.write(sheet_seek_position, 0, new_response['result']['data'][0]['preDrawTime'][:10])
# 在表格的第一个位置处写入时间,意即:data
record_number = 1 # 记录数据的一个判断值,设置为第一次,应该是要放在最外面的啦
list_data_number = []
# 设置一个空列表来存储一天之中的连续挂的期数
dict_time_record = {}
for k in range(1152):
# record_number = 1,应该要放外面
# 记录数据的一个判断值,设置为第一次
if k < 1150:
new_result1 = reverse_list(new_response["result"]["data"])[k]
new_result2 = reverse_list(new_response["result"]["data"])[k + 1]
new_result3 = reverse_list(new_response["result"]["data"])[k + 2]
data1 = new_result1['preDrawCode'].split(',')
data2 = new_result2['preDrawCode'].split(',')
data3 = new_result3['preDrawCode'].split(',')
for m in range(10):
if m == 0:
if data2[0] == data1[1]:
N += 1
if (data2[0] in low_list and data3[0] in high_list) or (data2[0] in high_list and data3[0] in low_list):
n += 1
# 如果命中了的话,本轮结束,开启下一轮
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1 # 初始化
else:
record_number += 1 # 没中,次数加一
# 自加一
break
elif m == 9:
if data2[9] == data1[8]:
N += 1
if (data2[9] in low_list and data3[9] in high_list) or (data2[9] in high_list and data3[9] in low_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1
else:
record_number += 1
break
else:
if data2[m] == data1[m + 1] or data2[m] == data1[m - 1]:
N += 1
if (data2[m] in low_list and data3[m] in high_list) or (data2[m] in high_list and data3[m] in low_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1
else:
record_number += 1
break
print(f"日期:{new_response['result']['data'][0]['preDrawTime'][:10]},总的梯子数为{N}个,一共有{n}次命中,一共有{N - n}次挂了")
sh.write(sheet_seek_position, 1, N)
sh.write(sheet_seek_position, 2, n)
sh.write(sheet_seek_position, 3, N - n)
# new_list_data_number = list_data_number.sort()
list_data_number.sort()
# 进行排序
dict_record = {}
# 设置空字典
for i in list_data_number:
if f"{i}" in dict_record.keys(): # 判断是否已经有了这个数字?
dict_record[f"{i}"] += 1
# 如果有的话,那么就会自加一
else: # 如果没有的话,那么就会创建并且赋值等于 1
dict_record[f"{i}"] = 1
# 创建一个新的字典元素,然后进行赋值为 1
# print(dict_record)
# print(f"买彩票第几次才中奖?")
# print(f"按照我们的规律买彩票的情况:")
for j in dict_record.keys():
if (int(j) >= 6) and (int(j) < 15):
print(f"买{j}次才中奖的次数为{dict_record[j]}")
print(dict_time_record[j])
str0 = ""
for letter in dict_time_record[j]:
str0 += letter
str0 += ", "
print(str0)
sh.write(sheet_seek_position, 4 + (int(j) - 6) * 2, dict_record[j])
# 写入几次
sh.write(sheet_seek_position, 4 + (int(j) - 6) * 2 + 1, str0[:-2])
# 注意这里应该要改为 -2
# 写入几次对应的时间
# print(j)
sheet_seek_position += 1
# 每次写完了以后,要对位置进行换行,换到下一行,从而方便下一行的写入
# 保存
wb.save('极速飞艇彩票分析结果.xls')
然后,我们只需要稍稍改变一点点算法,其他的部分是完全一样的啦,从而即就是可以实现极速赛车的数据分析了啦。
修改的代码在下面列出来了:
for m in range(10):
if m == 0:
if data2[0] == data1[1]:
N += 1
if (data2[0] in low_list and data3[0] in low_list) or (data2[0] in high_list and data3[0] in high_list):
n += 1
# 如果命中了的话,本轮结束,开启下一轮
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1 # 初始化
else:
record_number += 1 # 没中,次数加一
# 自加一
break
elif m == 9:
if data2[9] == data1[8]:
N += 1
if (data2[9] in low_list and data3[9] in low_list) or (data2[9] in high_list and data3[9] in high_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1
else:
record_number += 1
break
else:
if data2[m] == data1[m + 1] or data2[m] == data1[m - 1]:
N += 1
if (data2[m] in low_list and data3[m] in low_list) or (data2[m] in high_list and data3[m] in high_list):
n += 1
list_data_number.append(record_number)
if f"{record_number}" in dict_time_record.keys():
dict_time_record[f"{record_number}"].append(new_result3['preDrawTime'][11:])
else:
dict_time_record[f"{record_number}"] = [new_result3['preDrawTime'][11:]]
# print(record_number)
record_number = 1
else:
record_number += 1
break
总结
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