JavaScript中的reduce()的5个用例
web前端开发
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2020-08-03 13:42
回调函数
Accumulator(累加器)——累加器累加回调函数的返回值。
Current Value(当前值)——处理数组的当前元素。
Current Index(当前索引)——处理数组当前元素的索引。
Source Array(源数组)
初始值
arr.reduce(callback(accumulator, currentValue[,index[,array]])[, initialValue])
const numbersArr = [67, 90, 100, 37, 60];
const total = numbersArr.reduce(function(accumulator, currentValue){
console.log("accumulator is " + accumulator + " current value is " + currentValue);
return accumulator + currentValue;
}, 0);
console.log("total : "+ total);
accumulator is 0 current value is 67
accumulator is 67 current value is 90
accumulator is 157 current value is 100
accumulator is 257 current value is 37
accumulator is 294 current value is 60
total : 354
JavaScript reduce用例
1、对数组的所有值求和
const studentResult = [67, 90, 100, 37, 60];
const total = studentResult.reduce((accumulator, currentValue) => accumulator +currentValue, 0);
console.log(total); // 354
2、对象数组中的数值之和
const studentResult = [
{ subject: '数学', marks: 78 },
{ subject: '物理', marks: 80 },
{ subject: '化学', marks: 93 }
];
const total = studentResult.reduce((accumulator, currentValue) => accumulator + currentValue.marks, 0);
console.log(total); // 251
3、展平数组
const twoDArr = [ [1,2], [3,4], [5,6], [7,8] , [9,10] ];
const oneDArr = twoDArr.reduce((accumulator, currentValue) => accumulator.concat(currentValue));
console.log(oneDArr);
// [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
4、按属性分组对象
const result = [
{subject: '物理', marks: 41},
{subject: '化学', marks: 59},
{subject: '高等数学', marks: 36},
{subject: '应用数学', marks: 90},
{subject: '英语', marks: 64},
];
let initialValue = {
pass: [],
fail: []
}
const groupedResult = result.reduce((accumulator, current) => {
(current.marks >= 50) ? accumulator.pass.push(current) : accumulator.fail.push(current);
return accumulator;
}, initialValue);
console.log(groupedResult);
{
pass: [
subject: ‘化学’, marks: 59 },
subject: ‘应用数学’, marks: 90 },
subject: ‘英语’, marks: 64 }
],
fail: [
subject: ‘物理’, marks: 41 },
subject: ‘高等数学’, marks: 36 }
]
}
5、删除数组中的重复项
const duplicatedsArr = [1, 5, 6, 5, 7, 1, 6, 8, 9, 7];
const removeDuplicatedArr = duplicatedsArr.reduce((accumulator, currentValue) => {
if(!accumulator.includes(currentValue)){
accumulator.push(currentValue);
}
return accumulator;
}, []);
console.log(removeDuplicatedArr);
// [ 1, 5, 6, 7, 8, 9 ]
总结
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