总结几种常见 验证码的解决方案，非常有用！

import tesserocrfrom PIL import Imageimage = Image.open('code2.jpg')image = image.convert('L')threshold = 127table = []for i in range(256):if i < threshold:        table.append(0)else:        table.append(1)image = image.point(table, '1')result = tesserocr.image_to_text(image)print(result)

# -*- coding: utf-8 -*-import cv2import numpy as np
imagepath = '9_1.png'img = cv2.imread(imagepath)gray = cv2.cvtColor ( img , cv2.COLOR_BGR2GRAY )ret, binary = cv2.threshold(gray,127,255,cv2.THRESH_BINARY)  
contours, hierarchy = cv2.findContours(binary,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)  #cv2.drawContours(img,contours,-1,(0,0,255),1)  for cnt in contours:
# 最小外界矩形的宽度和高度    width, height = cv2.minAreaRect(cnt)[1]
if width* height > 100:# 最小的外接矩形        rect = cv2.minAreaRect(cnt)        box = cv2.boxPoints(rect)  # 获取最小外接矩形的4个顶点
        box = np.int0(box)print box
if 0 not in box.ravel():
#绘制最小外界矩形for i in range(4):                cv2.line(img, tuple(box[i]), tuple(box[(i+1)%4]), 0)  # 5            theta = cv2.minAreaRect(cnt)[2]if abs(theta) <= 45:print('图片的旋转角度为%s.'%theta)

#     angle = thetaprint theta            cv2.imshow("img", img)  cv2.waitKey(0)  

import numpy as npimport math

def ease_out_expo(x):"""    曲线函数    :param x:    :return:"""if x == 1:return 1else:return 1 - pow(2, -10 * x)

def get_tracks(distance, seconds):"""    轨迹生成函数    :param distance: 滑动总距离    :param seconds: 滑动总时间    :return:"""    tracks = [0]  # 存放轨迹的数组    offsets = [0]  # 存放滑动总距离的记录数组for t in np.arange(0.0, seconds, 0.1):  # 产生一个数列如[0.0, 0.1, 0.2, 0.3]        offset = round(ease_out_expo(t/seconds) * distance)  # 根据时间t计算在曲线上的滑动距离        tracks.append(offset - offsets[-1])  # 本次计算的距离减去上一次移动的距离，得到本次的轨迹        offsets.append(offset)  # 至本次滑动了的总距离return offsets, tracks

a, b = get_tracks(138, 3)print(a, b)

def get_tracksb(distance):"""    根据物理的先加速再减速规律计算    :param distance:    :return:"""    distance += 20  # 加上20是为了滑动超过缺口再回滑    v = 0  # 初速度    t = 0.2  # 以0.2秒为一个计算周期    forward_tracks = []  # 轨迹记录数组    current = 0  # 初始移动距离    mid = distance * 3 / 5  # 减速阀值即五分之三的距离加速剩下距离减速while current < distance:  # 总移动距离等于输入距离时结束if current < mid:  # 加速状态            a = 2  # 加速度为+2else:  # 减速状态            a = -3  # 加速度-3
        s = v * t + 0.5 * a * (t ** 2)  # 计算0.2秒周期内的位移        v = v + a * t  # 计算本次周期后的速度        current += s  # 将之前移动的总距离，加上本次0.2秒周期内移动的距离        forward_tracks.append(round(s))  # 记录本次0.2秒周期内的移动距离为轨迹
    back_tracks = [-3, -3, -2, -2, -2, -2, -2, -1, -1, -1]  # 手动将开头加上的20，生成减去轨迹，即回滑轨迹return {'forward_tracks': forward_tracks, 'back_tracks': back_tracks}

https://2captcha.com/in.php?key= 上面获取的API KEY &method=geetest>= 某验参数&challenge= 某验参数&api_server=api-na.geetest.com(可选)&pageurl= 滑动验证码所在的网页地址

OK|2122988149 or as JSON {"status":1,"request":"2122988149"}

https://2captcha.com/res.php?key=API KEY&action=get&id=2122988149

{"challenge":"1a2b3456cd67890e12345fab678901c2de","validate":"09fe8d7c6ba54f32e1dcb0a9fedc8765","seccode":"12fe3d4c56789ba01f2e345d6789c012|jordan"}