测试工程师之Python面试题(附答案)-技术圈

1、请把字符串“abcde”里面的字符，逐个，打印出来

ss="abcdefgh"

for i in ss:

print(i)

2、对字符串“www.autotestplat.com"，输出为“com.autotestplat.www"

ss = "www.autotestplat.com"

list_ss = list(ss.split('.'))

list_ss.reverse()

print(".".join(list_ss))

3、把一个列表里面的数字元素，去重，如 {1,1,2,2,3,3,4,4,5,5}

aa = [1,1,2,2,3,3,4,4,5,5,5]

bb = list(set(aa))

print(bb)

4、用递归实现数字的阶乘，N！，n=9时，s=9*8*7*6*5*4*3*2*1

def a(n):

if int(n)<= 1:

return 1

else:

return n*a(n-1)

print(a(9))

5、对字符串

{"a":"0","b":"1","d":"11","e":"22","f":"33"},

输出字典 {'a':'1','b':'1','d':'11','e':'22','f':'33'}

ss= '{"a":"0","b":"1","d":"11","e":"22","f":"33"}'

dict_ss = eval(ss)

print(dict_ss)

6、以下代码：

a="05550550"

print(a.index("x")

运行结果是：

ValueError: substring not found

7、以下几行字符串

fin one ：13700010001 15 52A

fin two ：13700020002 15 52B

fin three：13700030003 15 52C

依次代表姓名：手机号楼栋号房间号

请输出

姓名：...，电话：...........，住址：......

str1 = 'fin one :13700010001 15 52A'

str2 = 'fin two :13700020002 15 52B '

str3 = 'fin three:13700030003 15 52C'

a1 = str1.split(':')

a11 = a1[1].split(' ')

a2 = str2.split(':')

a22 = a2[1].split(' ')

a3 = str3.split(':')

a33 = a3[1].split(' ')

print("姓名:"+a1[0]+",电话:"+a11[0]+",住址:"+a11[1]+" "+a11[2])

print("姓名:"+a2[0]+",电话:"+a22[0]+",住址:"+a22[1]+" "+a22[2])

print("姓名:"+a3[0]+",电话:"+a33[0]+",住址:"+a33[1]+" "+a33[2])

8、实现一个冒泡排序

data = [2,10,7,8,9,5,4,1]

def bubble_sort(arr):

for i in range(len(data)-1):

for j in range(len(data)-1-i):

if data[j]>data[j+1]:

data[j+1],data[j]=data[j],data[j+1]

return data

print(bubble_sort(data))